**how to find the min point and plot the graph using secant**

23/09/2006Â Â· If you set 4x-5 equal to 0, then x = 5/4, this is where the point is minimum. Its only a minimum for a quadratic if the coefficient in front of the xsqrd is positive (i.e. 2 in this case). If it had been negative then it would be a maximum.... 27/06/2016Â Â· I'm really keen to understand if it is possible to calculate maximum and minimum points of cubic graphs WITHOUT the use of calculus. However easy it is, I want to explore this possibility. I'd be most grateful if you would be able to please clarify this predicament. Thanks, Doctor Math.

**how to find the min point and plot the graph using secant**

1/04/2011Â Â· i have a graph such as the one shown however the data points arent the same for each cycle as the graph suggests - just wanted to show the type of curve i have. what i want to do is to be able to get the maximum point only on the curve, per cycle, based on the data i have. i.e the y â€¦... Thus, the only points at which a function can have a local maximum or minimum are points at which the derivative is zero, as in the left hand graph in figure 5.1.1, or the derivative is undefined, as in the right hand graph.

**Minimum point of the graph? Yahoo Answers**

23/09/2006Â Â· If you set 4x-5 equal to 0, then x = 5/4, this is where the point is minimum. Its only a minimum for a quadratic if the coefficient in front of the xsqrd is positive (i.e. 2 in this case). If it had been negative then it would be a maximum.... 1) To be a minimum point, the graph must change direction from decreasing to increasing. 2) To be a maximum point, the graph must change direction from increasing to decreasing. 3) To be an inflection point, the graph doesn't change direction.

**How do I find the minimum distance from a point to a graph?**

Of course if you look at the graph, you can see that the left side of the graph starts from negative infinity, and the right side goes on to infinity. So, in this case we are talking about a relative maximum at point X = -.3147 and a relative minimum at point X= 2.648.... Of course if you look at the graph, you can see that the left side of the graph starts from negative infinity, and the right side goes on to infinity. So, in this case we are talking about a relative maximum at point X = -.3147 and a relative minimum at point X= 2.648.

## How To Find The Minimum Point Of A Graph

### how do i find the minimum/maximum point using a quadratic

- how do i find the minimum/maximum point using a quadratic
- How do I find the minimum distance from a point to a graph?
- MATH 136 Minimizing the Distance from a Point to Function
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## How To Find The Minimum Point Of A Graph

### Thus, the only points at which a function can have a local maximum or minimum are points at which the derivative is zero, as in the left hand graph in figure 5.1.1, or the derivative is undefined, as in the right hand graph.

- The graphical solution explains how to use the graphic calculator to draw the graph of y = 4x 2 + 12x + 10, how to change the scale of the axes on the display, how to find the minimum value and the point of intersection of the graph with the y axis.
- Is there another way of finding the minimum point? For example, writing a code such as to input an x-value (from x = 1 to 2 with an interval of 0.1) to derive the corresponding f(x) and then getting matlab to figure out which f(x) is the minimum?
- Finding coordinates of a point in a graph. Ask Question. up vote 0 down vote favorite. I have generated a scatter plot using python. How to find out the coordinates of a point? from matplotlib import pyplot as plt x = [min(max(L2.real, 0.2), 0.3) for L2 in L] y = [min(max(L2.imag, 0), 0.004) for L2 in L] plt.scatter(x, y) plt.show() python matplotlib. share improve this question. edited Feb
- Can you find the local maximum and local minimum in the graph above? Yes, of course. Now look at the same places and think about what the slope is at those two locations.

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